h
AT=b⋅h2A_T=\dfrac{b\cdot h}{2}AT=2b⋅h
AQ=L2A_Q=L^2AQ=L2
L2=b⋅h2L^2=\dfrac{b\cdot h}{2}L2=2b⋅h
L=b⋅h2L=\sqrt{\dfrac{b\cdot h}{2}}L=2b⋅h
L=b⋅h2L=\sqrt{b\cdot\dfrac{h}{2}}L=b⋅2h
L=b2⋅hL=\sqrt{\dfrac{b}{2}\cdot h}L=2b⋅h
5-Quadrat equivalent a triangle.
b
